Answer :
Answer:
The answer is in the explanation
Step-by-step explanation:
Mean value = [tex]\bar x[/tex] = 438
(a) The data appeared to be centered towards 438.
There are little or no skew.
There is no outliers.
(b) yes
(c) standard deviation = s = 14.8955
95% confidence interval = [tex]+- t_{df} * s\sqrt{n}[/tex]
[tex]438 +- 2.12 * 14.8955 /\sqrt{17}[/tex]=
= (430.3415, 445.6585)
(d) Test statistic
t = [tex](438 - 450)/{14.8955\sqrt17} }[/tex]
t = -3.3216
p -value is correctly given in option b.
No, 450 is not a plausible valaue.