Answer :
Explanation:
You use either the formula E=hf or E=hcλ.
Explanation:
h is Planck's Constant, f is the frequency, c is the speed of light, and λ is the wavelength of the radiation.
EXAMPLE 1
Calculate the energy of a photon of radiation whose frequency is 5.00×1014Hz.
Solution 1
E=hf=6.626×10−34J⋅s×5.00×1014s−1=3.31×10−19J
The energy is 3.31×10−19J.
EXAMPLE 2
Calculate the energy of a photon of radiation that has a wavelength of 3.3 µm.
Solution 2
E=hcλ=6.626×10−34J⋅s×2.998×108m⋅s−13.3×10−6m=6.0×10−20J
Taking into account the definition of photon and energy of a photon, the energy of a photon with a frequency of 2.80×10¹⁴ s⁻¹ is 1.85528×10⁻¹⁹ J.
The energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon."
A photon is characterized by an energy, denoted by E, determined by the expression:
E = h×f
where h is Planck's constant (h), whose value is h = 6.626×10⁻³⁴ J×s
In this case, you know that f=2.80×10¹⁴ s⁻¹. Then:
E=6.626×10⁻³⁴ J×s × 2.80×10¹⁴ s⁻¹
Solving:
E= 1.85528×10⁻¹⁹ J
The energy of a photon with a frequency of 2.80×10¹⁴ s⁻¹ is 1.85528×10⁻¹⁹ J.
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