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The uniform 12 ft pole is hinged to the truck bed and released from the vertical position as the truck starts from rest with an acceleration of 3 ft/sec^2.

If the acceleration remains constant during the motion of the pole, calculate the angular velocity ω of the pole as it reaches the horizontal position.

Answer :

Answer:

w = 0.886 rad / s

Explanation:

Angular and linear variables are related

       a = α r

where a is the linear acceleration, α the angular acceleration and r the radius of gyration

         α = a / r

the angular velocity we can find it

         w² = w₀² + 2 α θ

the initial angular velocity is zero, the angles to be horizontal is

    θ = π/ 2  rad

     

we substitute

          w = √ 2 a / r  θ

we calculate

          w = √ (2 3/12 π/2)

          w = 0.886 rad / s

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