Answer :
Answer:
[tex] s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
[tex] s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808[/tex]
And the answer for this case would be :
[tex]s= 3.81[/tex] after round the value
Step-by-step explanation:
We have the following data set given:
31, 33, 36, 41, 34
If we want to find the standard deviation we need to find first the sample mean with this formula:
[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
And replacing we got:
[tex] \bar X = \frac{31+33+36+41+34}{5}= \frac{175}{5}= 35[/tex]
Now we can find the sampel deviation with this formula:
[tex] s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] s =\sqrt{\frac{(31-35)^2 +(33-35)^2 +(36-35)^2 +(41-35)^2 +(34-35)^2}{5-1}} =3.808[/tex]
And the answer for this case would be :
[tex]s= 3.81[/tex] after round the value