Answer :
Answer:
Step-by-step explanation:
Question not written well
The equation of the ball is meant to be in a parabola or trajectory form.
So, h = -4.912t² + 24.5t + 1
The ball will hit the ground when the height is 0
I.e. h= 0
Therefore,
-4.912t² + 24.5t + 1 = 0
Using almighty formula,
a = -4.912 b = 24.5 c = 1
t = (-b±√b²-4ac) / 2a
t = (-24.5±√24.5²-4×-4.912 × 1) / 2 × -4.912
t = (-24.5±√600.25 + 19.648) / 9.824.
t = (-24.5 ± 24.898) / 9.824
So,
t = (-24.5 + 24.898) / 9.824
t = 0.398 / 9.824
t = 0.04seconds
Or
t = (-24.5 - 24.898) / 9.824
t = -5.03 seconds
So, we are going to discard the negative time,
t = 0.04 second is the correct time the ball will hit the ground
Answer: After 5.02 seconds
Step-by-step explanation:
The correct equation in the question is h= -4.912 t²+ 24.5t + 1
Hi, when the ball hits the ground, height =0.
So, replacing in the equation:
0= -4.912 t²+ 24.5t + 1
For: ax2+ bx + c
x =[ -b ± √b²-4ac] /2a (quadratic formula)
Replacing with the values given:
x =[ -24.5 ± √24.5²-4(-4.912)1] /2(-4.912)
x = [ -24.5 ± √600.25+19.648] /-9.824
x = [ -24.5 ± √619.898] /-9.824
x = [ -24.5 ± 24.90] /-9.824
Positive:
x = [ -24.5 +24.90 ] /-9.824 = -0.04 seconds
Negative:
x = [ -24.5 -24.90] /-9.824 = 5.02 seconds
Since time can't be negative, the answer is 5.02 seconds.
Feel free to ask for more if needed or if you did not understand something.