Answer:
[tex]X=0.027mol[/tex]
Explanation:
Hello,
In this case, we need to apply a mole mass relationship via the molar mass of the magnesium bromide (MgBr2). For it, we first compute its molar mass as shown below:
[tex]M=m_{Mg}+2*m_{Br}=24.305 g/mol+2*79.904 g/mol\\\\M=184.113g/mol[/tex]
Hence, we can understand that 1 mole of magnesium bromide contains 184.113 grams of mangnesium bromide, for that reason, for 5 grams of magnesium bromide we have the following moles:
[tex]184.113g\rightarrow 1mol\\5.0g \rightarrow X\\\\X=\frac{5.0g*1mol}{184.113g} \\\\X=0.027mol[/tex]
Best regards.
