A current of 2 Amps flows through a circuit containing a motor with resistance 12 Ohms. How many Joules of energy is converted if the motor runs for one minute?

Answer :

Chelboy

Answer:2880 joules

Explanation:

Current=2 amps

Resistance=12 ohms

Time=1 minute=60 seconds

Energy=(current)^2 x resistance x time

Energy=2^2 x 12 x 60

Energy=2 x 2 x 12 x 60

Energy=2880

Energy=2880 joules

The energy dissipated in the motor circuit is 2,880 J.

The given parameters;

  • current in the circuit, I = 2 A
  • resistance, R = 12 ohms
  • time of current dissipation, t = 1 mins

The energy dissipated in the motor circuit is calculated as follows;

[tex]E = I^2Rt[/tex]

[tex]E = (2)^2 \times 12 \times 60\\\\E = 2,880 \ J[/tex]

Thus, the energy dissipated in the motor circuit is 2,880 J.

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