Answer :
Answer:2880 joules
Explanation:
Current=2 amps
Resistance=12 ohms
Time=1 minute=60 seconds
Energy=(current)^2 x resistance x time
Energy=2^2 x 12 x 60
Energy=2 x 2 x 12 x 60
Energy=2880
Energy=2880 joules
The energy dissipated in the motor circuit is 2,880 J.
The given parameters;
- current in the circuit, I = 2 A
- resistance, R = 12 ohms
- time of current dissipation, t = 1 mins
The energy dissipated in the motor circuit is calculated as follows;
[tex]E = I^2Rt[/tex]
[tex]E = (2)^2 \times 12 \times 60\\\\E = 2,880 \ J[/tex]
Thus, the energy dissipated in the motor circuit is 2,880 J.
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