Answer :

wegnerkolmp2741o

Answer:

1.   2

2.  6

3.  2

4.  3

5.  1

6.   1

Step-by-step explanation:

First put the data in order from smallest to largest

2,2,2,3,3,6

The minimum is 2

The maximum is 6

The median is 2,2,2    ,3,3,6  is between the 2 and 3  (2+3)/2 = 2.5

The 1st quartile is 2,2,2  is the middle number   = 2

The third quartile is   3,3,6  is the middle number is 3

The interquartile range is 3-2 =1

The mean average deviation is

First find the mean: ( 2+2+2+3+3+6)/6 =18/6 = 3

Then find how far each point is from the mean

(3-2) + (3-2) + (3-2) + (3-3) + (3-3) + (6-3)  = 6

Divide this by the number of data points

6/6 =1

09pqr4sT

Answer:

[tex]\Large \boxed{1. \ 2} \\ \\ \Large \boxed{2. \ 6} \\\\ \Large \boxed{3. \ 2} \\\\ \Large \boxed{4. \ 3} \\\\ \Large \boxed{5. \ 1} \\\\ \Large \boxed{6. \ 1}[/tex]

Step-by-step explanation:

The minimum value of the data set is the lowest value in the data set.

2, 2, 2, 3, 3, 6

2 is the lowest value. 2 is the minimum value of the data set.

The maximum value of the data set is the highest value in the data set.

2, 2, 2, 3, 3, 6

6 is the highest value. 6 is the maximum value of the data set.

The first quartile of the data set is 2, 2, 2, the middle value is 2.

The third quartile of the data set is 3, 3, 6, the middle value is 3.

The interquartile range of the data set is:

[tex]\sf IQR=Q_3-Q_1 = 3-2=1[/tex]

The mean average deviation from the mean is:

[tex]\sf \displaystyle m \ (mean)=\frac{sum \ of \ terms}{number \ of \ terms} = \frac{2+2+2+3+3+6}{6} =\frac{18}{6} =3[/tex]

[tex]\sf \displaystyle mean \ average \ deviation = \frac{(m-x_1)+(m-x_2)...}{number \ of \ terms}[/tex]

[tex]\sf \displaystyle \frac{(3-2)+(3-2)+(3-2)+(3-3)+(3-3)+(6-3)}{6}=\frac{6}{6} =1[/tex]

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