Answered

A bag contains pieces of paper with the following numbers on them: 1, 2, 3, 5, 7, 9, 10, 11.
Find the probability of each event. Write your answer as a decimal rounded to 3 decimal places
A. Picking an odd number and then the 10, with replacement:
B. Picking 2 even numbers in a row, without replacement:
C. Picking a number greater than 4 and then the 1, without replacement:

Answer :

Answer:

See below in bold.

Step-by-step explanation:

There are 2 even and 6 odd numbers in the list.

A.

Prob(Picking an odd number) = number of odd numbers / total of numbers

= 6/8 = 0.75.

Prob(Picking a 10) = 1/8 = 0.125.

Answer = 0.75 * 0.125 = 0.09375

= 0.094 to 3 dec. places.

B.

Prob( Picking and even) = 2/8 = 1/4.

Prob( Picking another even without replacement) = 1/7.

Answer = 1/4 * 1/7 = 1/28

= 0.036 to 3 dec. places.

C.

There are 5 numbers greater than 4.

Prob(Picking a number > 4) =  5/8.

Prob( Picking a 1 without replacement) = 1/7.

Answer = 5/8 * 1/7

= 5/56

= 0.089 to 3 dec. places.

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