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Today at 12:10 PM
Mathematics

Answered

How do you solve x^2-4X-12=0

Answer :

Today at 12:14 PM

x² - 4x - 12 = 0

Factor the left side: (x + 2) · (x - 6) = 0

The equation is true if either factor is zero.

If (x + 2) = 0 then x = -2 .

If (x - 6) = 0 then x = 6 .

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