someone help me it’s due tm

Answer:
C
Step-by-step explanation:
The angle between the tangent and the radius at the point of contact is right.
Thus the triangle is right with hypotenuse = 3 + 8 = 11 ( 3 is the radius )
Using Pythagoras' identity
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
x² + 3² = 11², that is
x² + 9 = 121 ( subtract 9 from both sides )
x² = 112 ( take the square root of both sides )
x = [tex]\sqrt{112}[/tex] = [tex]\sqrt{16(7)}[/tex] = [tex]\sqrt{16}[/tex] × [tex]\sqrt{7}[/tex] = 4[tex]\sqrt{7}[/tex] → C