Answer :

[tex] \dfrac{1}{3}y + \dfrac{1}{4} = \dfrac{5}{12} [/tex] 

[tex] \dfrac{y}{3} + \dfrac{1}{4} = \dfrac{5}{12} [/tex]  

[tex] \dfrac{y}{3}= \dfrac{5}{12}- \dfrac{1}{4} [/tex]     [tex]Subtract \ 1/4 \ from \ both \ sides[/tex]
 
[tex] \dfrac{y}{3}= \dfrac{1}{6} [/tex] 

[tex]y= \dfrac{1}{6}*3 [/tex]        [tex] Multiply \ both \ sides \ by \ 3[/tex]

[tex]y= \dfrac{3}{6} [/tex] 

[tex]= y = \dfrac{1}{2} [/tex]         [tex]Simplify [/tex]

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