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The standard Gibbs energy of reaction, ÄG°, for the dissociation of phenol is 56.4 kJ mol-1 at 298 K. Calculate the pKa of phenol.

a.
9.88
c.
4.12
b.
22.8
d.
5.24​

Answer :

Answer:

a.

9.88

Explanation:

ΔG = - 2.303 RT log Ka

ΔG is change in free energy at temperature T , Ka is equilibrium constant

- 56.4 x 10³ = 2.303 x 8.31 x 298 logKa

- log Ka = 9.88 .

pKa = 9.88 .

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