2x2−5x=3
I think the first step would be to
Subtract 3 from both sides
2x2−5x−3=3−3
2x2−5x−3=0
Then
For this equation: a=2, b=-5, c=-3
2x2+−5x+−3=0
Lastly you would
Use quadratic formula with a=2, b=-5, c=-3
I think your answer would then have to be...
x = 3 or x = −1 /2
Answer:
3 and -1/2
Step-by-step explanation:
The quadratic formula is [tex](- b +/- \ sqrt{b^2-4ac} )/2a[/tex], for ax^2+bx+c=0.
You're equation is 2x^2-5x=3. Subtract 3 on both sides to get 2x^2-5x-3=0. Now we plug this in into the quadratic formula to get [tex](5+/-\sqrt{25-(-24)} )/4[/tex] which is equal to [tex](5+/- \sqrt{49} )/4 = (5+/- 7)/4.[/tex]There are 2 solutions, one being (5+7)/4= 12/4= 3, and the other being (5-7)/4=-2/4=-1/2/
