Given the two similar solids as shown in the diagram:
a. Volume of Solid B = [tex]\mathbf{480 $ cm^3}[/tex]
b. Surface Area of Solid A = [tex]\mathbf{35 $ cm^2}[/tex]
Given that the two solids, A and B, are similar, therefore, assuming they have a pair of corresponding dimension, given as, a and b respectively, thus:
- [tex]\mathbf{\frac{Vol_A}{Vol_B} = \frac{a^3}{b^3}}[/tex] (ratio of their volume to their corresponding sides)
- [tex]\mathbf{\frac{A_A}{A_B} = \frac{a^2}{b^2}}[/tex] (ratio of their surface area to their corresponding sides)
Thus:
a. Volume of Solid A = [tex]60 $ cm^3[/tex]
a = 3 cm
b = 6 cm
[tex]\frac{60}{Vol_B} = \frac{3^3}{6^3}\\\\\frac{60}{Vol_B} = \frac{27}{216}\\\\Vol_B = \frac{216 \times 60}{27} \\\\\mathbf{Vol_B = 480 $ cm^3}[/tex]
a. Area of Solid B = [tex]140 $ cm^2[/tex]
a = 3 cm
b = 6 cm
[tex]\frac{A_A}{140} = \frac{3^2}{6^2}\\\\\frac{A_A}{140} = \frac{9}{36}\\\\A_A = \frac{9 \times 140}{36} \\\\\mathbf{A_A = 35 $ cm^2}[/tex]
- Therefore, given the two similar solids as shown in the diagram:
a. Volume of Solid B = [tex]\mathbf{480 $ cm^3}[/tex]
b. Surface Area of Solid A = [tex]\mathbf{35 $ cm^2}[/tex]
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