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Answered

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have altogether?

A. 74 coins

B. 75 coins

C. 76 coins

D. 77 coins

Answer :

Answer:

if   x = the number of nickles   and     x-34 = the number of dimes                    then .05x + .10(x-34) = 4.85               or          .15x = 8.25               x = 55

So, nickles = x = 55

dimes = (x-34) = 21

55+ 21 = 76 So, that means your answer is C. 76 coins

Step-by-step explanation:

Answer:

the correct answer is C

Step-by-step explanation:

Set the 34 more nickels aside.

--> pairs of 1 nickel & 1 dime each worth 15 cents & a total of $3.15 ($4.85 - $1.70)

315/15 = 21 pairs

--> 21 dimes and 55 nickels

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