If 5(4 − x) < y + 12 and y + 12 < 3x + 1, then which statement is true?


5(4 − x) < 3x + 1

5(4 − x) + 3x + 1 = y + 12

3x + 1 < 5(4 + x)

3x + 1 − 5(4 − x) = y + 12

Answer :

Answer:

5(4 − x) < 3x + 1

Step-by-step explanation:

Since 5(4 − x) has a value less than y + 12, and 3x + 1 has a value greater than y + 12, the transitive property can relate the two expressions in a single inequality.

The transitive property of inequality is stated below.

If a < b and b < c, then a < c.

So, the statement 5(4 − x) < 3x + 1 is true.

The statement 5(4 − x) < 3x + 1 is true.

What is inequality ?

The mathematical statement in which numbers, variables of both sides are not equal, is called inequality.

Inequality is denoted by the symbols < , > , ≤ , ≥

What is the true statement ?

Given that, 5(4 − x) < y + 12 and y + 12 < 3x + 1

We know that, according to the transitive property of inequality,

If A < B and B < C then A < C

So, Here 5(4 − x) < y + 12 and y + 12 < 3x + 1 ⇒ 5(4 − x) < 3x + 1

Learn more about inequality here :

https://brainly.com/question/11613554

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