You are monitoring the sound intensity and sound intensity level from two different sources (#1 and #2) of sound at a specific site. You determine that at that site, source #1 has a sound intensity of 38.3 W/m2 and source 2 has an intensity level that is 2.6 dB greater than the intensity level of source 1. Determine the sound intensity of source #2. W/m2

Answer :

Answer:

The sound intensity of source #2 is 38.3 W/m²

Explanation:

Given;

sound intensity of source #1, I₁ =  38.3 W/m²

sound intensity of source #2, I₂ = 2.6 dB greater than 38.3 W/m²

To determine he sound intensity of source #2 in W/m², we must convert 2.6 dB to sound intensity in W/m².

[tex]10log\frac{I (W/m^2)}{I_o} = I (dB)\\\\10log\frac{I }{1*10^{-12}} = 2.6\\\\log(\frac{I }{1*10^{-12}})^{10} = 2.6\\\\10^{2.6} = (\frac{I }{1*10^{-12}})^{10} \\\\10^{\frac{2.6}{10}} = \frac{I }{1*10^{-12}}\\\\1.8197 = \frac{I }{1*10^{-12}}\\\\I = 1.8197 *1*10^{-12} = 1.8197 *10^{-12} \ W/m^2[/tex]

Thus, sound intensity of source #2 = 38.3 W/m² + 1.8197 x 10⁻¹² W/m² = 38.3 W/m²

Therefore, the sound intensity of source #2 is 38.3 W/m²

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