Answered

Given P(A)=0.5P(A)=0.5, P(B)=0.71P(B)=0.71 and P(A\cap B)=0.415P(A∩B)=0.415, find the value of P(A|B)P(A∣B), rounding to the nearest thousandth, if necessary.

Answer :

MathPhys

Answer:

0.585

Step-by-step explanation:

P(A|B) = P(A∩B) / P(B)

P(A|B) = 0.415 / 0.71

P(A|B) = 0.585

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