please help me fast i will give first answer brainliest!!

Answer:
(-1,-18) is the coordinate of the vertex.
Step-by-step explanation:
We can obtain the vertex by taking the derivative and equating it to zero. I know this because the the slope of the tangent line at the vertex has to be equal to zero.
the derivative would be 4x + 4 = 0, where x = -1.
Plugging x into the original value we will end up with the y coordinate.
Hope this helps.
Answer:
see below
Step-by-step explanation:
f(x) = 2x^2 +4x-16
Factor out 2
f(x) = 2 (x^2 +2x) -16
Complete the square inside the parentheses
Take the coefficient of x, divide by 2 and square it
(2/2)^1
f(x) = 2 ( x^2+2x+1 -1 ) -16
Bring the -1 outside the parentheses
f(x) = 2(x^2+2x+1)-2 -16
f(x) = 2(x+1)^2 - 18
This is in vertex form
y = a(x-h)^2 + k where ( x,k) is the vertex
f(x) = 2(x - -1)^2 - 18
The vertex is (-1,-18)