The graph of a line has a slope of -3 and passes through the point (-6,-4).
What is the equation of the line in point-slope form?
Oy + 4 = -3(x + 6)
y + 6 = -3(x + 4)
y-4 = -3(x-6)
y-6 = -3(x – 4)

Answer :

Answer:

(A) y+4=-3(x+6)

Step-by-step explanation:

The point-slope form of the equation of a line whose slope is m and passes through the point [tex](x_1, y_1)[/tex] is: [tex]y-y_1=m(x-x_1)[/tex]

Given the point: [tex](x_1, y_1)=(-6,-4)[/tex]

Slope, m=-3

[tex]x_1=-6\\y_1=-4[/tex]

Substituting these values into:  [tex]y-y_1=m(x-x_1)[/tex], we obtain the point slope form of the equation:

[tex]y-(-4)=-3(x-(-6))\\\\y+4=-3(x+6)[/tex]

The correct option is A.

The point-slope form of the line is y+4=-3(x+6). So, option A is correct.

Important information:

  • Slope of a line is -3.
  • Line passes through the point (-6,-4).

Point-slope form:

The point-slope form of a line is:

[tex]y-y_1=m(x-x_1)[/tex]

Where, [tex]m[/tex] is the slope and [tex](x_1,y_1)[/tex] is the point on the line.

Substitute [tex]m=-3,x_1=-6,y_1=-4[/tex],

[tex]y-(-4)=-3(x-(-6))[/tex]

[tex]y+4=-3(x+6)[/tex]

Therefore, the correct option is A.

Find out more about 'Point-slope form' here:

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