Answer :
Answer:
new force is 6 times of the initial force.
Explanation:
Let the charges on two objects is q₁ and q₂. The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Objects 1 and 2 attract each other with a electrostatic force of 18.0 units
If the charge of Object 1 is doubled and the charge of object 2 is tripled, it means, [tex]q_1'=2q_1[/tex] and [tex]q_2'=3q_2[/tex]. New force is given by :
[tex]F'=\dfrac{kq_1'q_2'}{r^2}\\\\F'=\dfrac{k(2q_1)(3q_2)}{r^2}\\\\F'=6\dfrac{kq_1q_2}{r^2}\\\\F'=6F[/tex]
So, the new electrostatic force between objects will become 6 times of the initial force.