a random sample size of 450 is drawn from a large population. The population standard deviation is 1.6. The sample mean is 27.9. Estimate the size of the population mean, including margin of error.

Answer:
The size of the population mean would be provided as:
mean +/- std/sqrt(sample size)
<=>
27.9 +/- 1.6/sqrt(450)
<=>
27.9 +/- 0.75
=> Option A is correct.
Hope this helps!
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Size of the population mean including the margin of error is option (a) 27.9±0.075
the standard deviation is a measure of the amount of variation or dispersion of a set of values
Mean is the average of the given numbers and is calculated by dividing the sum of given numbers by the total number of numbers
Given,
Random sample size = 450
Population standard deviation = 1.6
Sample mean = 27.9
Size of the population mean = Mean ± Standard deviation / ([tex]\sqrt{sample size}[/tex])
=27.9±[tex](\frac{1.6}{\sqrt{450} })[/tex]
=27.9±0.075
Hence, Size of the population mean including the margin of error is option (a) 27.9±0.075
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