Answer:
The balanced equation is [tex]C_{6} H_{12}O_{6}+6O_{2}[/tex] → [tex]6CO_{2}+6H_{2}O[/tex]
The number of grams of oxygen needed to react with 30 grams of glucose is 30 grams.
Explanation:
[tex]\frac{30 g(glucose)}{}|\frac{1mol(glucose)}{180.156g(glucose)} |\frac{6mol(oxygen)}{1mol(glucose)} |\frac{32g(oxygen)}{1mol(oxygen)}[/tex]
The set-up shown is how this problem can be solve. This is called stoichiometry. Stoichiometry refers to math amongst the elements or the compounds. Now, we solve the equation above.
[tex]\frac{5760}{180.156}[/tex]
Divide the expression.
[tex]\frac{5760}{180.156}[/tex] = 31.9722
Now, we round this answer.
31.9722 → 32
The number of grams of oxygen needed is 32 grams.
Hope this helps!
