Answer :
Answer:
± 1.51
Explanation:
The mean standard deviation = 1.21 since the three data sets had 1.21 standard deviations each
95% probability = 0.95
calculate standard error is calculated as = [tex]\sqrt{MSE}[/tex] = [tex]\sqrt{\frac{SSE}{N-K} }[/tex]
[tex]\sqrt{\frac{(n-1)s^2}{15-3} }[/tex]= [tex]\sqrt{\frac{4(1.2)^2}{12} }[/tex]
= [tex]\sqrt{\frac{5.76}{12} }[/tex] = [tex]\sqrt{0.48}[/tex] = 0.6928
calculate the margin of error
[tex]tan_{0.05/2.12} * se[/tex]
from statistical table equation becomes
2.179 * 0.6928 = 1.5096 ≈ ± 1.51