Answer :
Answer:
48 in
Step-by-step explanation:
The diagonal of the inscribed square equals the diameter of the circle.
1. Calculate the diagonal of the square
d = 2r = 2 × 6√2 in =12√2 in
2. Calculate the side of the square
∆ACB is an isosceles right triangle.
We can use Pythagoras' Theorem to calculate the length of a side s.
[tex]\begin{array}{rcl}s^{2} + s^{2} & = & (12\sqrt{2})^{2}\\2s^{2} & = & 144 \times 2\\s^{2} & = & 144\\s & = & \text{12 in}\\\end{array}[/tex]
3. Calculate the perimeter of the square
P = 4s = 4 × 12 in = 48 in
The perimeter of the square is 48 in.

The perimeter of the square in inches is 48 square inches
The diameter of the circle is twice the given radius
Given the following:
radius = 6√2
diameter = 2(6√2)
diameter = 12√2
The diagonal of the cube inscribed will be equal to the diameter of the circle.
Next is to get the side length "l" of the square using the Pythagoras theorem. According to the theorem:
l²+l² = (12√2)²
2l² = 144(2)
l² = 288/2
Take the square root of both sides
l² = 144
l = √144
l = 12inches
Next is to get the perimeter of the square
Perimeter of the square = 4L
Perimeter of the square = 4(12)
Hence the perimeter of the square is 48 square inches
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