Answer:
Each team needs two people for a 3-legged race.
Therefore, the number of orders (combinations) of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28
Answer: 28
Each team needs two people for a 3-legged race.
Therefore, the number of orders of 2 people at a time from 8 is
₈C₂ = 8!/(2!6!)
= (8*7*6!)/(2*6!)
= (8*7)/2
= 56/2
= 28
After solving, you will be able to know that your answer is 28