Answer :

sdhadli26
The triangles are congruent. So.

Triangle ABC is 24 inch^2 and BC is 4 inches.
The area of a triangle is 0.5 x base x height. The will be 12 because 12 x 4 x 0.5 which equals 24.

Triangle DEF is half the size of ABC because bc is 4 and EF is 2 showing it’s half. This then means the height will be half which then mean it will be 6.

This then means we can use the equation to work it out. So. 6 x 0.5 x 2 = 6in^2

The answer is 6inches^2
varshamittal029

If the area of ΔBAC = 24 in², the area of ΔEDF is 6 in².

What are similar triangles?

If two triangles' angles are congruent and their corresponding sides are proportionate, they are considered similar. To put it another way, similar triangles are the same in shape but not necessarily in size. If ΔPQR and ΔMNO are two similar triangles, then we can write it as ΔPQR ∼ ΔMNO.

Statement:

The square of the ratio of any pair of their respective sides is equal to the ratio of the areas of two similar triangles.

How to solve this problem?

Since ΔBAC ∼ ΔEDF, we can use the above statement to find the area of ΔEDF. Let the area of ΔEDF be x in². Given that length of EF and BC is 2 in and 4 in respectively.

So, we have to solve this equation,

24/x = 4²/2²

Now, 24/x = 16/4

i.e. 24/x = 4

i.e. 4x = 24

i.e. x = 24/4 = 6

Therefore the area of ΔEDF is 6 in².

Learn more about similar triangles here -

https://brainly.com/question/16819417

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