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You may remember that the area of a triangle is A=12B⋅H, where B is the base of the triangle and H is the height.

Suppose that the area of a triangle is 9 square feet, and the base is 2 times the height. Find the base of the triangle, in feet.

Do not type the units in your answer.

Answer :

osikbro

Answer:

6

Step-by-step explanation:

Assuming that the base is b and the height is h:

[tex]\dfrac{bh}{2}=9 \\\\b=2h[/tex]

Substitute:

[tex]\dfrac{2h(h)}{2}=9 \\\\h^2=9 \\\\h=3 \\\\b=2h=6[/tex]

Hope this helps!

abidemiokin

The base of the triangle is 6feets given that the area of the triangle is 9 square feet.

Given that the area of a triangle is expressed as:

[tex]A=\frac{1}{2}bh[/tex]

b is the base of the triangle

h is the height of the triangle

Given that A = 9 square feet

If the base is 2 times the height, then [tex]b=2h[/tex]

Substitute b=2h into the area of the triangle above:

[tex]A=\frac{2h\times h}{2}\\9=\frac{2h^2}{2}\\9=h^2\\h^2=9\\h=\sqrt{9}\\h= 3[/tex]

Get the base of the triangle:

Recall that b = 2h

[tex]b=2(3)\\b=6[/tex]

Hence the base of the triangle is 6feets.

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