Answer :
sn = (n(a1 + a52)) / 2
n = 52
a1 = 1
a52 = 154
s52 = (52(1 + 154)) / 2
s52 = (52(155)) / 2
s52 = 8060/2
s52 = 4030 <==
n = 52
a1 = 1
a52 = 154
s52 = (52(1 + 154)) / 2
s52 = (52(155)) / 2
s52 = 8060/2
s52 = 4030 <==
Answer: 4030
Step-by-step explanation:
We know that sum of an arithmetic series with first term as 'a' and the last term as 'l' is given by :-
[tex]S_n=\frac{n}{2}(a+l)[/tex], where n is the number of terms
In the given situation, the number of terms = 52
The first term = 1
The 52th term = 154
Then the sum of 52 terms ids given by :-
[tex]S_{52}=\frac{52}{2}(1+154)\\\Rightarrow\ S_{52}=(26)(155)=4030[/tex]
Hence, the sum of the series =4030