Answer:
[tex]\dfrac{2(y-2x)}{3y-5x}[/tex]
Step-by-step explanation:
When you simplify the numerator and the denominator, you find they both have denominators of xy. So, the ratio of those is the ratio of their numerators.
[tex]\dfrac{\dfrac{2}{x}-\dfrac{4}{y}}{\dfrac{-5}{y}+\dfrac{3}{x}}=\dfrac{\left(\dfrac{2y-4x}{xy}\right)}{\left(\dfrac{-5x+3y}{xy}\right)}=\dfrac{2y-4x}{-5x+3y}\\\\=\boxed{\dfrac{2(y-2x)}{3y-5x}}[/tex]
