Answer :
Answer:
80.25%
Explanation:
Data provided in the question
[tex]X \sim N (513,120)[/tex]
Mean = 513
Standard deviation = 120
Now
[tex]P(400 < x < 750) = P (\frac{400 - 513}{120} <z < \frac{750 - 513}{120})[/tex]
After solving this
= P (-0.9417 < Z < 1.975)
= P (-0.9417 < Z < 0) + P (0 < Z < 1.975)
= 0.3264 + 0.4761
or by apply the Z table or excel command
Like this
NORMSDIST(1.98) - NORMSDIST(-0.94)
= 0.9761 - 0.1736
= 80.25%
Hence the probability is 80.25%