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A presidential candidate plans to begin her campaign by visiting the capitals in 4 of 46 states. What is the probability that she selects the route of four specific capitals?

Answer :

Answer:

The probability is 1/3,916,440

Explanation:

Here, we want to calculate the probability that she selects the route of four specific capitals.

The first thing to do here is to calculate the number of routes possible.

This is a permutation problem and the total number of possible ways will be 46 P 4 = 46!/(46-4)! = 46!/42! = 3,916,440

Now the probability of selecting the route of four specific capitals will be 1/3,916,440

The probability of her choosing a route out of those 4 would be 0.000000255.

The data given;

  • The number of routes = 4
  • Total number of available route = 46

Permutation

To solve this problem, we need to use permutation to find the number of ways she can take the routes.

[tex]P = \frac{46!}{(46-4)!}\\P = 3916440[/tex]

The number of ways she can travel is 3916440.

Probability

This chance or likelihood of an event to occur.

[tex]P = \frac{outcome of an event}{total number of events in the space} \\P = \frac{1}{3916440}\\P = 2.55*10^-^7[/tex]

The probability of her taking any of the routes is 0.000000255.

Learn more about probabilities here;

https://brainly.com/question/25275758

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