Answer :
Answer: y = -2
Step-by-step explanation:
f(x) = A cos (Bx - C) + D
↓
center line (aka midline)
f(x) = 2 cos (3x - 5π/6) - 2
↓
midline = -2
The midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
What is cos function?
It is defined as a function that is sin-cos wave in nature, and it has a domain of all real numbers and lies between the [a, a] where is the amplitude of the function.
It is given that the cos function is:
f(x) = 2cos(3x - 5π/6) - 2
As we know, the standard form of the cos function is:
f(x) = Acos(Bx - C) + D
Here, A is the amplitude
B is the period of the cos function
C is the phase shift of the cos function
D is the vertical shift of the cos function/midline
On comparing:
D = -2
The midline:
y = -2
Thus, the midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
Learn more about the cos function here:
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