Answer:
12 m
Step-by-step explanation:
Given that the design, ABCD, was dilated to get a photocopy, EFGH, a scale factor or ratio was multiplied by the original lengths of the design to get the new measurement of the photocopy.
Thus, we are given the ratio, CD:GH = 2:3.
This means, any of the corresponding lengths of both figures would be in that same ratio.
Using the ratio of the design to the photocopy, 2:3, we can find the length of side EH of the photocopy.
The corresponding side of EH in the design is AD = 8m. Thus, AD to EH = ⅔
[tex] \frac{AD}{EH} = \frac{2}{3} [/tex]
[tex] \frac{8}{EH} = \frac{2}{3} [/tex]
Cross multiply
[tex] 3*8 = 2*EH [/tex]
[tex] 24 = 2*EH [/tex]
Divide both sides by 2 to make EH the subject of formula
[tex] \frac{24}{2} = \frac{2*EH}{2} [/tex]
[tex] 12 = EH [/tex]
The length of side EH = 12 m
