On the coordinate plane below, Point P, is located at (2,-3) and point Q is located at (-4,4). Find the distance between points, P and Q

Answer:
[tex]d = \sqrt{85}[/tex] or d ≈ 9.22
Step-by-step explanation:
Distance formula:
[tex]d = \sqrt{(2 - (-4))^2 + (-3- 4)^2} \\d = \sqrt{36+ 49}\\d = \sqrt{85} \\[/tex]