Answer:
[tex]tan(A) = \frac{2\sqrt{15}}{11}[/tex]
Step-by-step explanation:
Given:
Right ∆ABC
AB = 61
BC = 60
AC = 11
Required:
Value of tan A in radical form
SOLUTION:
[tex] tan(A) = \frac{opposite}{adjacent} [/tex]
Opposite = 60
Adjacent = 11
[tex] tan(A) = \frac{60}{11} [/tex]
[tex] tan(A) = \frac{\sqrt{4*15}}{11} [/tex]
[tex]tan(A) = \frac{2\sqrt{15}}{11}[/tex]
