Answer :

A 1.89 pints of blood would contain 873 grams of platelets.

To calculate the amount of platelets present in 1.89 pints, it is first necessary to transform this unit of volume into liters:

  • 1 pint = 473.2 mL

                                  [tex]1.89 \times 473.2 = 894.3 mL[/tex]

  • 1000 L = 1mL

         

                                         [tex]\frac{894.3}{1000}= 0.84L[/tex]

Now, just calculate the amount of platelets present in 0.84L:

                                    [tex]\frac{1.04\times10^{3}g}{xg}=\frac{1L}{0.84L}[/tex]

                               

                                       x = 873 grams

So, a 1.89 pints of blood would contain 873 grams of platelets.

Learn more about transformation of units in: brainly.com/question/10667910

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