Answer :
Answer:
There are 6.94x10⁶ C of the negative electric charge contained in the electrons of all the lithium atoms in the container.
Explanation:
We have 3 moles of electrons (e⁻) in 1 mol of Li, so the quantity of negative electric charge is:
[tex] \frac{3 moles \thinspace e^{-}}{1 mol Li}*24 moles Li*\frac{6.022 \cdot 10^{23} e^{-}}{1 mol \thinspace e^{-}}*\frac{1.60 \cdot 10^{-19} C}{1 e^{-}} = 6.94 \cdot 10^{6} C [/tex]
Therefore, there are 6.94x10⁶ C of the negative electric charge contained in the electrons of all the lithium atoms in the container.
I hope it helps you!