Answer :
Answer:
32.29 mL
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
2HCl(aq)+ Ba(OH)2(aq) —> BaCl2(aq) + 2H2O
From the balanced equation above, the following were obtained:
Mole ratio of the acid (nA) = 2
Mole ratio of the base (nB) = 1
Next, data were obtained from. This include the following:
Molarity of acid, HCl (Ma) = 0.3428 M
Volume of acid, HCl (Va) =.?
Molarity of base, Ba(OH)2 (Mb) = 0.2350 M
Volume of base, Ba(OH)2 (Vb) = 23.55 mL
Finally, we shall determine the volume of the acid, HCl required for the reaction as follow:
MaVa /MbVb = nA/nB
0.3428 × Va / 0.2350 × 23.55 = 2/1
Cross multiply
0.3428 × Va = 0.2350 × 23.55 × 2
Divide both side by 0.3428
Va = (0.2350 × 23.55 × 2) / 0.3428
Va = 32.29 mL
Therefore, the volume of acid, HCl required for the reaction is 32.29 mL