Answer:
We need to solve this equation:
[tex]3[-x + (2 x + 1)] = x-1[/tex]
Firstly, we remove the parenthesis, as it's getting summed and it isn't necessary:
[tex]3[-x+2x+1]=x-1[/tex]
Now we operate the brackets:
[tex]3(x+1)=x-1[/tex]
We calculate tha prenthesis:
[tex]3x + 3 = x - 1[/tex]
And finally, we substract x and 3 on both sides. a
[tex]3x + 3 - x - 3 = x - 1 -x - 3[/tex]
[tex]2x = -4[/tex]
[tex]\bold{x = \frac{-4}{2} = -2}[/tex]
Now, we can verify for x = -2:
[tex]3[-(-2)+(2*(-2)+1)]=-3[/tex]
[tex]3[2+(-4+1)]=-3[/tex]
[tex]3[2+(-3)]=3[/tex]
[tex]3[2-3]=-3[/tex]
[tex]3[-1]=-3[/tex] TRUE
