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A proton is placed in a uniform electric field of 2550 N/C.

Required:
a. Calculate the magnitude of the electric force felt by the proton.
b. Calculate the proton's acceleration.
c. Calculate the proton's speed after 1.40 µs in the field, assuming it starts from rest.

Answer :

hopemichael95

Answer:

A. Using

F= Eq

We substitute

= 2550NC x 1.6*10-19C

4.08*10^-16N

B.

Acceleration = F/m

So a = 4.08x10^ -16/1.67*10^-27

2.4*10^11m/s²

C.

Velocity= a x t

So V= 2.4x10^11 x 1.4*10-6

3.4*105m/s

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