A ladder is leaning against a building. The distance from the building to the bottom of the ladder is 7 feet. The ladder is 25 feet long. How high up the building is the top of the ladder?

Answer :

Answer:

Let x equal the length of the ladder.

Then the distance from the ground to the top of the ladder is (x-2).

The distance from the ladder to the building is 6.

The ground and the building wall form a right angle, therefore use Pythagorean Theorem.

x^2 = (x-2)^2 +6^2

x^2 = x^2 - 4x + 4 + 36

x^2 = x^2 - 4x + 40

Subtract x^2 from both sides leaving.

0 = -4x + 40

Add -40 to both sides.

-40 = -4x

Divide both sides by -4.

-40/-4 = -4x/-4

     10 FEET = x  THE LENGTH OF THE LADDER.

xKelvin

Answer:

24 feet

Step-by-step explanation:

The ladder leaning against the building resembles a right triangle. So, we can use the Pythagorean Theorem.

The Pythagorean Theorem is:

[tex]a^2+b^2=c^2[/tex]

Where a and b are the legs of the right triangle and c is the hypotenuse.

We know that the distance from the building is 7 feet. This means that the base is 7. So, we can substitute 7 into either a or b.

We know the ladder itself is 25 feet long. So, the hypotenuse is 25. Substitute that for c. Therefore:

[tex]7^2+b^2=25^2[/tex]

We need to solve for b to figure out how high up the building is the top of the ladder. Evaluate the squares:

[tex]49+b^2=625[/tex]

Subtract 49 from both sides:

[tex]b^2=576[/tex]

Take the square root of both sides:

[tex]b=24[/tex]

So, the top of the ladder is 24 feet up from the building.

And we're done!

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