SmartyAJ
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This is a double question. Part 1: 5(2x - 4) = 30. Solve for x Part 2: 5x + 3 - x + 2 = 41. Solve for x. I will mark Brainliest to whoever solves both parts as well as explains it.

Answer :

wegnerkolmp2741o

Answer:

see below

Step-by-step explanation:

Part 1: 5(2x - 4) = 30.

Distribute

10x -20 = 30

Add 20 to each side

10x-20+20 =30+20

10x = 50

Divide by 10

10x/10 = 50/10

x =5

Part 2: 5x + 3 - x + 2 = 41

Combine like terms

4x +5 = 41

Subtract 5 from each side

4x+5-5 = 41-5

4x = 36

Divide by 4

4x/4 = 36/4

x = 9
PART 1:
5(2x-4)=30
Multiply both 2x and -4 by 5

10x-20=30
Then add 20 to cancel it out, but once u do something to that side u must do it to the other side. So add 20 to 30 which is 50.

10x=50

10x/10= 50/10
Divide both side by 10

X=5



PART 2:
5x + 3 - x + 2 = 41

4x + 5 = 41
Combine the like terms

4x=36
Then subtract 5 from both sides to cancel to get 4x by itself

4x/4=36/4
Then divide both sides by 4

X=9

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