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A runner has an original velocity of 6 m/s and slows to a final velocity of 0 m/s. If the runner covers a
displacement of 12 m while slowing down, how long time) did it take the runner to stop?

Answer :

MathPhys

Answer:

4 s

Explanation:

Given:

Δx = 12 m

v₀ = 6 m/s

v = 0 m/s

Find: t

Δx = ½ (v + v₀) t

12 m = ½ (0 m/s + 6 m/s) t

t = 4 s

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