GEOMETRY: need some help on these equations, i'm giving a lot of points for this.

Answer:
1) ML=93
2) GE=58
Step-by-step explanation:
1)
We want to find ML.
So, we need to find x first.
Note that the entire segment, NK, is the addition of the segments NM, ML, and LK. So:
[tex]NM+ML+LK=NK[/tex]
And we know their equations. So, substitute 110+4x for NM, x+103 for ML, 70 for LK, and x+243 for NK. Thus:
[tex](110+4x)+(x+103)+(70)=x+243[/tex]
On the left, combine like terms:
[tex](4x+x)+(110+103+70)=x+243[/tex]
Add:
[tex]5x+283=x+243[/tex]
Subtract 283 from both sides:
[tex]5x=x-40[/tex]
Subtract x from both sides:
[tex]4x=-40[/tex]
Divide both sides by 4:
[tex]x=-10[/tex]
So, the value of x is -10.
Substitute this into ML to find it. So:
[tex]ML=(-10)+103[/tex]
Add:
[tex]ML=93[/tex]
And we're done!
2)
Here, we want to find GE. This means solving for x again.
Note that HF plus FE equates to the entire segment.
HG plus GE also equates to the entire segment.
Thus:
[tex]HF+FE=HG+GE[/tex]
Substitute 3x-129 for HF and 4 for FE.
Substitute 13x-993 for HG and 3x-185 for GE. Thus:
[tex](3x-129)+(4)=(13x-993)+(3x-185)[/tex]
Combine like terms on both sides:
[tex](3x)+(-129+4)=(13x+3x)+(-993-185)[/tex]
Add or subtract:
[tex]3x-125=16x-1178[/tex]
Add 1178 to both sides:
[tex]3x+1053=16x[/tex]
Subtract 3x from both sides:
[tex]1053=13x[/tex]
Divide both sides by 13:
[tex]x=81[/tex]
So, the value of x is 81.
To find out GE, GE is the 3x-185. So:
[tex]GE=3(81)-185[/tex]
Multiply:
[tex]GE=243-185[/tex]
Subtract:
[tex]GE=58[/tex]
And we're finished!