Answer :

The first option 12a - 20
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Answer:

[tex] \boxed{\sf f(2a - 3) = 12a - 20} [/tex]

Step-by-step explanation:

Function given:

⇒f(x) = 6x - 2

Substitute 2a - 3 into the function in place of x:

⇒f(2a - 3) = 6(2a - 3) - 2

Expand bracket:

⇒f(2a - 3) = 12a - 18 - 2

Add the like terms:

⇒f(2a - 3) = 12a - 20

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