Answer :
Answer:
Its duration is 1.85*10⁻³ s or 1.85 ms
Explanation:
The intensity of electric current I is defined as the amount of electric charge Q (measured in Coulombs) that passes through a section of a conductor in each unit of time. The letter I is used to name the Intensity and its unit is the Ampere (A).
The intensity of electric current is expressed as:
[tex]I=\frac{Q}{t}[/tex]
where:
I: Intensity expressed in Amps (A)
Q: Electric charge expressed in Coulombs (C)
t: Time expressed in seconds (s)
Being:
- I= 19500 A
- Q=36 C
- t=?
Replacing:
[tex]19500 A=\frac{36 C}{t}[/tex]
Solving:
19500 A*t= 36 C
[tex]t=\frac{36 C}{19500 A}[/tex]
t= 1.85*10⁻³ s= 1.85 ms (being 1 s= 1,000 ms)
Its duration is 1.85*10⁻³ s or 1.85 ms