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What would happen if N2 were added to N2(g) + O2(g) = 2NO(9) at

equilibrium?

O A. Keq would decrease

O B. More No would form.

O C. More O2 and No would form.

O D. More N2 and Oz would form.

Answer :

Balanced chemical equation is :

[tex]N_2(g)+O_2(g)-->2NO(g)[/tex]

It is given that the equation is in equilibrium.

We need to find what will happen if we add more [tex]N_2[/tex] is added .

By Le Chatelier's principle :

Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.

It means production of the side where content is added will decrease and concentration on other side will increase .

So , more NO would form .

Therefore, option B. is correct.

Hence, this is the required solution.

The study of chemicals is called chemistry.

The correct answer is B.

According to the principle, the reaction goes from the higher side to the lower side.

According to the question, N2 is added to the reaction which will lead to an increase in the amount of N2 in the reactant.

More amount in reactant will lead to the formation of more product and the in the equation more NO will form.

Hence, the correct answer is B that is More No would form.

For more information, refer to the link:-

https://brainly.com/question/25305623

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