Answer :

nickpetrun3
2(3x-1)=8x-20
SIMPLY

6x-2=8x-20
SUBTRACT 6x ON BOTH SIDES

-2=2x-20
ADD 20 TO BOTH SIDES

18=2x
DIVIDE 2 ON BOTH SIDES

X=9
SUBSTITUTE

3(9)-1

27-1

26

BC=26

Answer:

[tex]BC=26[/tex]

Step-by-step explanation:

Start with:

[tex]AB+BC=AC[/tex]

Since [tex]B[/tex] is the midpoint, we also know that:

[tex]AB=BC[/tex]

Knowing this, we can use a system of equations and substitute [tex]AB[/tex] for [tex]BC[/tex] in the equation we started with:

[tex]AB+AB=AC[/tex]

Let's identify our values:

[tex]AB=3x-1\\AC=8x-20[/tex]

Substitute:

[tex]3x-1+3x-1=8x-20[/tex]

Combine like terms:

[tex]6x-2=8x-20[/tex]

Add [tex]20[/tex] to both sides of the equation:

[tex]6x+18=8x[/tex]

Subtract [tex]6x[/tex] from both sides of the equation:

[tex]18=2x[/tex]

Divide by the coefficient of [tex]x[/tex], which is [tex]2.[/tex]

[tex]x=9[/tex]

Substitute [tex]9[/tex] into [tex]3x-1[/tex]

[tex]3(9)-1[/tex]

Solve:

[tex]AB=26[/tex]

Remember that [tex]AB=BC[/tex], thus:

[tex]BC=26[/tex]

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